Consider the concentration of the standard sodium carbonate solution is c moldm-3 and v mL of hydrochloric acid is required to neutralize 25 mL of this standard sodium carbonate solution.
The reaction that occurs is:
2 HCl + Na2CO3 ~ 2 NaCl + H2O + CO2
From the above reaction it is clear that the neutralization of 1 mole of sodium
carbonate requires 2 moles of hydrochloric acid.
25 mL of the carbonate solution used contains
25c divided by 1000 = moles of sodium carbonate.
Therefore the neutralization requires
25cx2 divided by 1000 = moles of hydrochloric acid.
Hence, find the concentration of the hydrochloric acid solution
No comments:
Post a Comment